Base | Representation |
---|---|
bin | 10010101111111100110111… |
… | …10011011010111011110111 |
3 | 12101222112211221101012011220 |
4 | 21113332123303122323313 |
5 | 20401003022241204310 |
6 | 223404445224401423 |
7 | 11453524650164244 |
oct | 1127763363327367 |
9 | 171875757335156 |
10 | 41230005022455 |
11 | 12156601a75687 |
12 | 475a799316273 |
13 | 1a00c852b5612 |
14 | a277859985cb |
15 | 4b7748bc4670 |
hex | 257f9bcdaef7 |
41230005022455 has 16 divisors (see below), whose sum is σ = 66280652628864. Its totient is φ = 21885121147680.
The previous prime is 41230005022433. The next prime is 41230005022471. The reversal of 41230005022455 is 55422050003214.
It is a happy number.
It is not a de Polignac number, because 41230005022455 - 216 = 41230004956919 is a prime.
It is a super-3 number, since 3×412300050224553 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6513425749 + ... + 6513432078.
It is an arithmetic number, because the mean of its divisors is an integer number (4142540789304).
Almost surely, 241230005022455 is an apocalyptic number.
41230005022455 is a deficient number, since it is larger than the sum of its proper divisors (25050647606409).
41230005022455 is a wasteful number, since it uses less digits than its factorization.
41230005022455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13026858046.
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 41230005022455 its reverse (55422050003214), we get a palindrome (96652055025669).
The spelling of 41230005022455 in words is "forty-one trillion, two hundred thirty billion, five million, twenty-two thousand, four hundred fifty-five".
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