Base | Representation |
---|---|
bin | 10010101111111101000100… |
… | …01111011100011101110011 |
3 | 12101222120010110121122111022 |
4 | 21113332202033130131303 |
5 | 20401003232414011201 |
6 | 223404504043410055 |
7 | 11453530431226106 |
oct | 1127764217343563 |
9 | 171876113548438 |
10 | 41230113032051 |
11 | 12156657a37909 |
12 | 475a80952392b |
13 | 1a00ca17a1a18 |
14 | a2779607273d |
15 | 4b775340c41b |
hex | 257fa23dc773 |
41230113032051 has 2 divisors, whose sum is σ = 41230113032052. Its totient is φ = 41230113032050.
The previous prime is 41230113032039. The next prime is 41230113032071. The reversal of 41230113032051 is 15023031103214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41230113032051 - 222 = 41230108837747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41230113032051.
It is not a weakly prime, because it can be changed into another prime (41230113032071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615056516025 + 20615056516026.
It is an arithmetic number, because the mean of its divisors is an integer number (20615056516026).
Almost surely, 241230113032051 is an apocalyptic number.
41230113032051 is a deficient number, since it is larger than the sum of its proper divisors (1).
41230113032051 is an equidigital number, since it uses as much as digits as its factorization.
41230113032051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 41230113032051 its reverse (15023031103214), we get a palindrome (56253144135265).
The spelling of 41230113032051 in words is "forty-one trillion, two hundred thirty billion, one hundred thirteen million, thirty-two thousand, fifty-one".
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