4123034001113 has 2 divisors, whose sum is σ = 4123034001114. Its totient is φ = 4123034001112.

The previous prime is 4123034001109. The next prime is 4123034001131. The reversal of 4123034001113 is 3111004303214.

Together with next prime (4123034001131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3410718256969 + 712315744144 = 1846813^2 + 843988^2 .

It is a cyclic number.

It is not a de Polignac number, because 4123034001113 - 2² = 4123034001109 is a prime.

It is not a weakly prime, because it can be changed into another prime (4123034009113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061517000556 + 2061517000557.

It is an arithmetic number, because the mean of its divisors is an integer number (2061517000557).

Almost surely, 2^{4123034001113} is an apocalyptic number.

It is an amenable number.

4123034001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4123034001113 is an equidigital number, since it uses as much as digits as its factorization.

4123034001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 4123034001113 its reverse (3111004303214), we get a palindrome (7234038304327).

The spelling of 4123034001113 in words is "four trillion, one hundred twenty-three billion, thirty-four million, one thousand, one hundred thirteen".