Base | Representation |
---|---|
bin | 10010101111111111001010… |
… | …11010100101010100000111 |
3 | 12101222200001000020211122220 |
4 | 21113333211122211110013 |
5 | 20401013034421302401 |
6 | 223405211543023423 |
7 | 11453600364425625 |
oct | 1127774532452407 |
9 | 171880030224586 |
10 | 41231240025351 |
11 | 12157086109632 |
12 | 475aa82a3ab73 |
13 | 1a01121113c6c |
14 | a278619da515 |
15 | 4b77bc326336 |
hex | 257fe56a5507 |
41231240025351 has 64 divisors (see below), whose sum is σ = 57408935021568. Its totient is φ = 26299617435648.
The previous prime is 41231240025301. The next prime is 41231240025407. The reversal of 41231240025351 is 15352004213214.
It is not a de Polignac number, because 41231240025351 - 215 = 41231239992583 is a prime.
It is a super-2 number, since 2×412312400253512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41231240025301) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1229042160 + ... + 1229075706.
It is an arithmetic number, because the mean of its divisors is an integer number (897014609712).
Almost surely, 241231240025351 is an apocalyptic number.
41231240025351 is a deficient number, since it is larger than the sum of its proper divisors (16177694996217).
41231240025351 is a wasteful number, since it uses less digits than its factorization.
41231240025351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34440.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 41231240025351 its reverse (15352004213214), we get a palindrome (56583244238565).
The spelling of 41231240025351 in words is "forty-one trillion, two hundred thirty-one billion, two hundred forty million, twenty-five thousand, three hundred fifty-one".
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