Base | Representation |
---|---|
bin | 100110011010000110… |
… | …100111101101000011 |
3 | 10221110002120210100211 |
4 | 212122012213231003 |
5 | 1133424433214134 |
6 | 30540115054551 |
7 | 2656653225133 |
oct | 463206475503 |
9 | 127402523324 |
10 | 41240132419 |
11 | 16542a85972 |
12 | 7bab2a1457 |
13 | 3b72c88925 |
14 | 1dd3186ac3 |
15 | 11157ed764 |
hex | 99a1a7b43 |
41240132419 has 2 divisors, whose sum is σ = 41240132420. Its totient is φ = 41240132418.
The previous prime is 41240132413. The next prime is 41240132429. The reversal of 41240132419 is 91423104214.
41240132419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41240132419 - 213 = 41240124227 is a prime.
It is a super-2 number, since 2×412401324192 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41240132413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20620066209 + 20620066210.
It is an arithmetic number, because the mean of its divisors is an integer number (20620066210).
Almost surely, 241240132419 is an apocalyptic number.
41240132419 is a deficient number, since it is larger than the sum of its proper divisors (1).
41240132419 is an equidigital number, since it uses as much as digits as its factorization.
41240132419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 41240132419 in words is "forty-one billion, two hundred forty million, one hundred thirty-two thousand, four hundred nineteen".
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