412412412433 has 4 divisors (see below), whose sum is σ = 471328471360. Its totient is φ = 353496353508.

The previous prime is 412412412403. The next prime is 412412412463. The reversal of 412412412433 is 334214214214.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334214214214 = 2 ⋅167107107107.

It is an interprime number because it is at equal distance from previous prime (412412412403) and next prime (412412412463).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-412412412433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412412412395 and 412412412404.

It is not an unprimeable number, because it can be changed into a prime (412412412403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29458029453 + ... + 29458029466.

It is an arithmetic number, because the mean of its divisors is an integer number (117832117840).

Almost surely, 2^412412412433 is an apocalyptic number.

It is an amenable number.

412412412433 is a deficient number, since it is larger than the sum of its proper divisors (58916058927).

412412412433 is an equidigital number, since it uses as much as digits as its factorization.

412412412433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58916058926.

The product of its digits is 18432, while the sum is 31.

Adding to 412412412433 its reverse (334214214214), we get a palindrome (746626626647).

The spelling of 412412412433 in words is "four hundred twelve billion, four hundred twelve million, four hundred twelve thousand, four hundred thirty-three".