Base | Representation |
---|---|
bin | 1100000000001011011… |
… | …00100111011010001101 |
3 | 1110102111201202202202021 |
4 | 12000011230213122031 |
5 | 23224110041123003 |
6 | 513243141530141 |
7 | 41536651630210 |
oct | 6000554473215 |
9 | 1412451682667 |
10 | 412412442253 |
11 | 1499a3087a39 |
12 | 67b18113951 |
13 | 2cb7607c826 |
14 | 15d648a3777 |
15 | aadb4892bd |
hex | 6005b2768d |
412412442253 has 4 divisors (see below), whose sum is σ = 471328505440. Its totient is φ = 353496379068.
The previous prime is 412412442229. The next prime is 412412442269. The reversal of 412412442253 is 352244214214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 412412442253 - 221 = 412410345101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412412442223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29458031583 + ... + 29458031596.
It is an arithmetic number, because the mean of its divisors is an integer number (117832126360).
Almost surely, 2412412442253 is an apocalyptic number.
It is an amenable number.
412412442253 is a deficient number, since it is larger than the sum of its proper divisors (58916063187).
412412442253 is an equidigital number, since it uses as much as digits as its factorization.
412412442253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58916063186.
The product of its digits is 61440, while the sum is 34.
Adding to 412412442253 its reverse (352244214214), we get a palindrome (764656656467).
The spelling of 412412442253 in words is "four hundred twelve billion, four hundred twelve million, four hundred forty-two thousand, two hundred fifty-three".
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