Base | Representation |
---|---|
bin | 111100000000111001100… |
… | …011111000110011011011 |
3 | 112121021010000022011220221 |
4 | 330000321203320303123 |
5 | 1020032211341010204 |
6 | 12434333503100511 |
7 | 603646615155526 |
oct | 74007143706333 |
9 | 15537100264827 |
10 | 4124134313179 |
11 | 1350043338441 |
12 | 5673502a1737 |
13 | 23bb9a6a025a |
14 | 10387579dbbd |
15 | 72428db7654 |
hex | 3c0398f8cdb |
4124134313179 has 2 divisors, whose sum is σ = 4124134313180. Its totient is φ = 4124134313178.
The previous prime is 4124134313147. The next prime is 4124134313261. The reversal of 4124134313179 is 9713134314214.
4124134313179 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4124134313179 - 25 = 4124134313147 is a prime.
It is not a weakly prime, because it can be changed into another prime (4124134313779) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062067156589 + 2062067156590.
It is an arithmetic number, because the mean of its divisors is an integer number (2062067156590).
Almost surely, 24124134313179 is an apocalyptic number.
4124134313179 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124134313179 is an equidigital number, since it uses as much as digits as its factorization.
4124134313179 is an evil number, because the sum of its binary digits is even.
The product of its digits is 217728, while the sum is 43.
The spelling of 4124134313179 in words is "four trillion, one hundred twenty-four billion, one hundred thirty-four million, three hundred thirteen thousand, one hundred seventy-nine".
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