Base | Representation |
---|---|
bin | 111100000000111111010… |
… | …100110011001110101011 |
3 | 112121021100202021110202222 |
4 | 330000333110303032223 |
5 | 1020032411120141413 |
6 | 12434351235544255 |
7 | 603652201161116 |
oct | 74007724631653 |
9 | 15537322243688 |
10 | 4124231021483 |
11 | 1350092990861 |
12 | 56737875b08b |
13 | 23bbb47306c1 |
14 | 10388457557d |
15 | 7243261bb08 |
hex | 3c03f5333ab |
4124231021483 has 2 divisors, whose sum is σ = 4124231021484. Its totient is φ = 4124231021482.
The previous prime is 4124231021431. The next prime is 4124231021489. The reversal of 4124231021483 is 3841201324214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4124231021483 - 222 = 4124226827179 is a prime.
It is not a weakly prime, because it can be changed into another prime (4124231021489) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062115510741 + 2062115510742.
It is an arithmetic number, because the mean of its divisors is an integer number (2062115510742).
Almost surely, 24124231021483 is an apocalyptic number.
4124231021483 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124231021483 is an equidigital number, since it uses as much as digits as its factorization.
4124231021483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 4124231021483 its reverse (3841201324214), we get a palindrome (7965432345697).
The spelling of 4124231021483 in words is "four trillion, one hundred twenty-four billion, two hundred thirty-one million, twenty-one thousand, four hundred eighty-three".
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