Base | Representation |
---|---|
bin | 111100000001000101001… |
… | …111101000100000010100 |
3 | 112121021121200010212122002 |
4 | 330001011033220200110 |
5 | 1020033112031031012 |
6 | 12434405144254432 |
7 | 603654515243525 |
oct | 74010517504024 |
9 | 15537550125562 |
10 | 4124330330132 |
11 | 1350133a4a921 |
12 | 5673a5a71418 |
13 | 23bbcc19160c |
14 | 10389382684c |
15 | 7243b1d67c2 |
hex | 3c0453e8814 |
4124330330132 has 6 divisors (see below), whose sum is σ = 7217578077738. Its totient is φ = 2062165165064.
The previous prime is 4124330330129. The next prime is 4124330330149. The reversal of 4124330330132 is 2310330334214.
It can be written as a sum of positive squares in only one way, i.e., 3681778089616 + 442552240516 = 1918796^2 + 665246^2 .
It is a junction number, because it is equal to n+sod(n) for n = 4124330330095 and 4124330330104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515541291263 + ... + 515541291270.
It is an arithmetic number, because the mean of its divisors is an integer number (1202929679623).
Almost surely, 24124330330132 is an apocalyptic number.
It is an amenable number.
4124330330132 is a deficient number, since it is larger than the sum of its proper divisors (3093247747606).
4124330330132 is a wasteful number, since it uses less digits than its factorization.
4124330330132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1031082582537 (or 1031082582535 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4124330330132 its reverse (2310330334214), we get a palindrome (6434660664346).
The spelling of 4124330330132 in words is "four trillion, one hundred twenty-four billion, three hundred thirty million, three hundred thirty thousand, one hundred thirty-two".
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