Base | Representation |
---|---|
bin | 1100000000001110101… |
… | …01101111011101001011 |
3 | 1110102120122121212022211 |
4 | 12000013111233131023 |
5 | 23224134120002311 |
6 | 513250004325551 |
7 | 41540435105362 |
oct | 6000725573513 |
9 | 1412518555284 |
10 | 412440000331 |
11 | 149a0769a807 |
12 | 67b253a38b7 |
13 | 2cb7b9ab198 |
14 | 15d683d87d9 |
15 | aaddace821 |
hex | 600756f74b |
412440000331 has 2 divisors, whose sum is σ = 412440000332. Its totient is φ = 412440000330.
The previous prime is 412440000299. The next prime is 412440000337. The reversal of 412440000331 is 133000044214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412440000331 - 25 = 412440000299 is a prime.
It is a super-2 number, since 2×4124400003312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (412440000337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206220000165 + 206220000166.
It is an arithmetic number, because the mean of its divisors is an integer number (206220000166).
Almost surely, 2412440000331 is an apocalyptic number.
412440000331 is a deficient number, since it is larger than the sum of its proper divisors (1).
412440000331 is an equidigital number, since it uses as much as digits as its factorization.
412440000331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 412440000331 its reverse (133000044214), we get a palindrome (545440044545).
The spelling of 412440000331 in words is "four hundred twelve billion, four hundred forty million, three hundred thirty-one", and thus it is an aban number.
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