Base | Representation |
---|---|
bin | 1100000000001110110… |
… | …10000110100000010001 |
3 | 1110102120201202221012111 |
4 | 12000013122012200101 |
5 | 23224134413041223 |
6 | 513250045025321 |
7 | 41540450605603 |
oct | 6000732064021 |
9 | 1412521687174 |
10 | 412441143313 |
11 | 149a08300521 |
12 | 67b25855241 |
13 | 2cb7bcbb4c4 |
14 | 15d68615173 |
15 | aaddc5830d |
hex | 6007686811 |
412441143313 has 2 divisors, whose sum is σ = 412441143314. Its totient is φ = 412441143312.
The previous prime is 412441143221. The next prime is 412441143347. The reversal of 412441143313 is 313341144214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 329777993169 + 82663150144 = 574263^2 + 287512^2 .
It is a cyclic number.
It is not a de Polignac number, because 412441143313 - 217 = 412441012241 is a prime.
It is not a weakly prime, because it can be changed into another prime (412441183313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206220571656 + 206220571657.
It is an arithmetic number, because the mean of its divisors is an integer number (206220571657).
Almost surely, 2412441143313 is an apocalyptic number.
It is an amenable number.
412441143313 is a deficient number, since it is larger than the sum of its proper divisors (1).
412441143313 is an equidigital number, since it uses as much as digits as its factorization.
412441143313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13824, while the sum is 31.
Adding to 412441143313 its reverse (313341144214), we get a palindrome (725782287527).
Subtracting from 412441143313 its reverse (313341144214), we obtain a palindrome (99099999099).
The spelling of 412441143313 in words is "four hundred twelve billion, four hundred forty-one million, one hundred forty-three thousand, three hundred thirteen".
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