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4124444113 is a prime number
BaseRepresentation
bin1111010111010110…
…0000010111010001
3101122102212110200101
43311311200113101
531421324202423
61521133052401
7204131124256
oct36565402721
911572773611
104124444113
1118271609a9
12971327101
1350964339a
142b1aa942d
151921577ad
hexf5d605d1

4124444113 has 2 divisors, whose sum is σ = 4124444114. Its totient is φ = 4124444112.

The previous prime is 4124444021. The next prime is 4124444123. The reversal of 4124444113 is 3114444214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2628920529 + 1495523584 = 51273^2 + 38672^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4124444113 is a prime.

It is a super-2 number, since 2×41244441132 = 34022078482520713538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4124444123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062222056 + 2062222057.

It is an arithmetic number, because the mean of its divisors is an integer number (2062222057).

Almost surely, 24124444113 is an apocalyptic number.

It is an amenable number.

4124444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124444113 is an equidigital number, since it uses as much as digits as its factorization.

4124444113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6144, while the sum is 28.

The square root of 4124444113 is about 64221.8351730936. The cubic root of 4124444113 is about 1603.6951202813.

Adding to 4124444113 its reverse (3114444214), we get a palindrome (7238888327).

The spelling of 4124444113 in words is "four billion, one hundred twenty-four million, four hundred forty-four thousand, one hundred thirteen".