Base | Representation |
---|---|
bin | 10010110000100010011000… |
… | …00001011000011011011001 |
3 | 12102001110211021102011212111 |
4 | 21120101030001120123121 |
5 | 20401320242140411101 |
6 | 223422015303512321 |
7 | 11455136646110416 |
oct | 1130211401303331 |
9 | 172043737364774 |
10 | 41250141341401 |
11 | 121640a5442093 |
12 | 4762678a586a1 |
13 | 1a02b43cabc45 |
14 | a2873600710d |
15 | 4b80268bb251 |
hex | 25844c0586d9 |
41250141341401 has 2 divisors, whose sum is σ = 41250141341402. Its totient is φ = 41250141341400.
The previous prime is 41250141341333. The next prime is 41250141341441. The reversal of 41250141341401 is 10414314105214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36887390103001 + 4362751238400 = 6073499^2 + 2088720^2 .
It is a cyclic number.
It is not a de Polignac number, because 41250141341401 - 225 = 41250107786969 is a prime.
It is not a weakly prime, because it can be changed into another prime (41250141341441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20625070670700 + 20625070670701.
It is an arithmetic number, because the mean of its divisors is an integer number (20625070670701).
Almost surely, 241250141341401 is an apocalyptic number.
It is an amenable number.
41250141341401 is a deficient number, since it is larger than the sum of its proper divisors (1).
41250141341401 is an equidigital number, since it uses as much as digits as its factorization.
41250141341401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 41250141341401 its reverse (10414314105214), we get a palindrome (51664455446615).
The spelling of 41250141341401 in words is "forty-one trillion, two hundred fifty billion, one hundred forty-one million, three hundred forty-one thousand, four hundred one".
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