Base | Representation |
---|---|
bin | 100110011010101101… |
… | …111010101000000001 |
3 | 10221110210222010211201 |
4 | 212122231322220001 |
5 | 1133440102333122 |
6 | 30541123541201 |
7 | 2660136620425 |
oct | 463255725001 |
9 | 127423863751 |
10 | 41250433537 |
11 | 16548881295 |
12 | 7bb282a801 |
13 | 3b75154571 |
14 | 1dd46a8b85 |
15 | 1116685a27 |
hex | 99ab7aa01 |
41250433537 has 2 divisors, whose sum is σ = 41250433538. Its totient is φ = 41250433536.
The previous prime is 41250433487. The next prime is 41250433577. The reversal of 41250433537 is 73533405214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23505795856 + 17744637681 = 153316^2 + 133209^2 .
It is a cyclic number.
It is not a de Polignac number, because 41250433537 - 215 = 41250400769 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41250433496 and 41250433505.
It is not a weakly prime, because it can be changed into another prime (41250433577) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20625216768 + 20625216769.
It is an arithmetic number, because the mean of its divisors is an integer number (20625216769).
Almost surely, 241250433537 is an apocalyptic number.
It is an amenable number.
41250433537 is a deficient number, since it is larger than the sum of its proper divisors (1).
41250433537 is an equidigital number, since it uses as much as digits as its factorization.
41250433537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 37.
The spelling of 41250433537 in words is "forty-one billion, two hundred fifty million, four hundred thirty-three thousand, five hundred thirty-seven".
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