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4125201245003 is a prime number
BaseRepresentation
bin111100000001111001001…
…001111010001101001011
3112121100212100220221020102
4330001321021322031023
51020041403004320003
612435031415120015
7604015222014116
oct74017111721513
915540770827212
104125201245003
111350540617083
125675a967300b
1323c00a743567
1410393737157d
157248c8ba588
hex3c07927a34b

4125201245003 has 2 divisors, whose sum is σ = 4125201245004. Its totient is φ = 4125201245002.

The previous prime is 4125201244991. The next prime is 4125201245021. The reversal of 4125201245003 is 3005421025214.

4125201245003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4125201245003 - 230 = 4124127503179 is a prime.

It is not a weakly prime, because it can be changed into another prime (4125201245603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062600622501 + 2062600622502.

It is an arithmetic number, because the mean of its divisors is an integer number (2062600622502).

Almost surely, 24125201245003 is an apocalyptic number.

4125201245003 is a deficient number, since it is larger than the sum of its proper divisors (1).

4125201245003 is an equidigital number, since it uses as much as digits as its factorization.

4125201245003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9600, while the sum is 29.

The spelling of 4125201245003 in words is "four trillion, one hundred twenty-five billion, two hundred one million, two hundred forty-five thousand, three".