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412534130101 = 491840191711
BaseRepresentation
bin1100000000011001111…
…00110100010110110101
31110102211012202011002121
412000030330310112311
523224332214130401
6513303210035541
741542660151242
oct6001474642665
91412735664077
10412534130101
11149a55841905
1267b50a18bb1
132cb95347a82
1415d76adc5c9
15aae6ec4ca1
hex600cf345b5

412534130101 has 4 divisors (see below), whose sum is σ = 413374322304. Its totient is φ = 411693937900.

The previous prime is 412534130093. The next prime is 412534130123. The reversal of 412534130101 is 101031435214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412534130101 - 23 = 412534130093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412534130161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420095365 + ... + 420096346.

It is an arithmetic number, because the mean of its divisors is an integer number (103343580576).

Almost surely, 2412534130101 is an apocalyptic number.

It is an amenable number.

412534130101 is a deficient number, since it is larger than the sum of its proper divisors (840192203).

412534130101 is an equidigital number, since it uses as much as digits as its factorization.

412534130101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 840192202.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 412534130101 its reverse (101031435214), we get a palindrome (513565565315).

The spelling of 412534130101 in words is "four hundred twelve billion, five hundred thirty-four million, one hundred thirty thousand, one hundred one".

Divisors: 1 491 840191711 412534130101