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412540433 is a prime number
BaseRepresentation
bin11000100101101…
…101111000010001
31001202021020002022
4120211231320101
51321102243213
6104534101225
713136351534
oct3045557021
91052236068
10412540433
111a1960808
12b61aa815
1367612586
143cb0aa1b
152633e308
hex1896de11

412540433 has 2 divisors, whose sum is σ = 412540434. Its totient is φ = 412540432.

The previous prime is 412540421. The next prime is 412540451. The reversal of 412540433 is 334045214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 378574849 + 33965584 = 19457^2 + 5828^2 .

It is a cyclic number.

It is not a de Polignac number, because 412540433 - 228 = 144104977 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (412545433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206270216 + 206270217.

It is an arithmetic number, because the mean of its divisors is an integer number (206270217).

Almost surely, 2412540433 is an apocalyptic number.

It is an amenable number.

412540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

412540433 is an equidigital number, since it uses as much as digits as its factorization.

412540433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 26.

The square root of 412540433 is about 20311.0913788501. The cubic root of 412540433 is about 744.4270976519.

Adding to 412540433 its reverse (334045214), we get a palindrome (746585647).

The spelling of 412540433 in words is "four hundred twelve million, five hundred forty thousand, four hundred thirty-three".