Base | Representation |
---|---|
bin | 111100000010000101010… |
… | …100011001010010010011 |
3 | 112121101101120221000222012 |
4 | 330002011110121102103 |
5 | 1020042312230222324 |
6 | 12435103545133135 |
7 | 604023250434002 |
oct | 74020524312223 |
9 | 15541346830865 |
10 | 4125405320339 |
11 | 1350635832986 |
12 | 567645a8a1ab |
13 | 23c040ac67b4 |
14 | 1039564d4c39 |
15 | 724a077c20e |
hex | 3c085519493 |
4125405320339 has 2 divisors, whose sum is σ = 4125405320340. Its totient is φ = 4125405320338.
The previous prime is 4125405320327. The next prime is 4125405320357. The reversal of 4125405320339 is 9330235045214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4125405320339 - 236 = 4056685843603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4125405320296 and 4125405320305.
It is not a weakly prime, because it can be changed into another prime (4125405320539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062702660169 + 2062702660170.
It is an arithmetic number, because the mean of its divisors is an integer number (2062702660170).
Almost surely, 24125405320339 is an apocalyptic number.
4125405320339 is a deficient number, since it is larger than the sum of its proper divisors (1).
4125405320339 is an equidigital number, since it uses as much as digits as its factorization.
4125405320339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 4125405320339 in words is "four trillion, one hundred twenty-five billion, four hundred five million, three hundred twenty thousand, three hundred thirty-nine".
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