Base | Representation |
---|---|
bin | 111100000110011000100… |
… | …011111000100111011011 |
3 | 112121211022102010022200111 |
4 | 330012120203320213123 |
5 | 1020131241404141402 |
6 | 12441150104345151 |
7 | 604245552152602 |
oct | 74063043704733 |
9 | 15554272108614 |
10 | 4130023115227 |
11 | 1352595419599 |
12 | 5685144751b7 |
13 | 23c5c87045c9 |
14 | 103c73904a39 |
15 | 72670d879d7 |
hex | 3c1988f89db |
4130023115227 has 2 divisors, whose sum is σ = 4130023115228. Its totient is φ = 4130023115226.
The previous prime is 4130023115201. The next prime is 4130023115243. The reversal of 4130023115227 is 7225113200314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4130023115227 - 215 = 4130023082459 is a prime.
It is not a weakly prime, because it can be changed into another prime (4130023115287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065011557613 + 2065011557614.
It is an arithmetic number, because the mean of its divisors is an integer number (2065011557614).
Almost surely, 24130023115227 is an apocalyptic number.
4130023115227 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130023115227 is an equidigital number, since it uses as much as digits as its factorization.
4130023115227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 4130023115227 in words is "four trillion, one hundred thirty billion, twenty-three million, one hundred fifteen thousand, two hundred twenty-seven".
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