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413004001101 = 3137668000367
BaseRepresentation
bin1100000001010001111…
…01001110111101001101
31110111000221220001221020
412000220331032331031
523231313011013401
6513421553024353
741560424041446
oct6005075167515
91414027801836
10413004001101
1114a176a9a94a
12680622550b9
132cc3b7b1253
1415dbd2902cd
15ab2338ad36
hex6028f4ef4d

413004001101 has 4 divisors (see below), whose sum is σ = 550672001472. Its totient is φ = 275336000732.

The previous prime is 413004001087. The next prime is 413004001127. The reversal of 413004001101 is 101100400314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413004001101 - 210 = 413004000077 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413004001301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68834000181 + ... + 68834000186.

It is an arithmetic number, because the mean of its divisors is an integer number (137668000368).

Almost surely, 2413004001101 is an apocalyptic number.

It is an amenable number.

413004001101 is a deficient number, since it is larger than the sum of its proper divisors (137668000371).

413004001101 is a wasteful number, since it uses less digits than its factorization.

413004001101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137668000370.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 413004001101 its reverse (101100400314), we get a palindrome (514104401415).

The spelling of 413004001101 in words is "four hundred thirteen billion, four million, one thousand, one hundred one".

Divisors: 1 3 137668000367 413004001101