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413004012601 is a prime number
BaseRepresentation
bin1100000001010001111…
…01010001110000111001
31110111000221220122201011
412000220331101300321
523231313011400401
6513421553153521
741560424120125
oct6005075216071
91414027818634
10413004012601
1114a176aa8554
126806225b8a1
132cc3b7b655b
1415dbd294585
15ab2338e451
hex6028f51c39

413004012601 has 2 divisors, whose sum is σ = 413004012602. Its totient is φ = 413004012600.

The previous prime is 413004012583. The next prime is 413004012647. The reversal of 413004012601 is 106210400314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371275736976 + 41728275625 = 609324^2 + 204275^2 .

It is a cyclic number.

It is not a de Polignac number, because 413004012601 - 213 = 413004004409 is a prime.

It is not a weakly prime, because it can be changed into another prime (413004012661) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206502006300 + 206502006301.

It is an arithmetic number, because the mean of its divisors is an integer number (206502006301).

Almost surely, 2413004012601 is an apocalyptic number.

It is an amenable number.

413004012601 is a deficient number, since it is larger than the sum of its proper divisors (1).

413004012601 is an equidigital number, since it uses as much as digits as its factorization.

413004012601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 413004012601 its reverse (106210400314), we get a palindrome (519214412915).

The spelling of 413004012601 in words is "four hundred thirteen billion, four million, twelve thousand, six hundred one".