413004044003 has 2 divisors, whose sum is σ = 413004044004. Its totient is φ = 413004044002.

The previous prime is 413004043967. The next prime is 413004044023. The reversal of 413004044003 is 300440400314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 413004044003 - 2²⁸ = 412735608547 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 413004044003.

It is not a weakly prime, because it can be changed into another prime (413004044023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206502022001 + 206502022002.

It is an arithmetic number, because the mean of its divisors is an integer number (206502022002).

Almost surely, 2^413004044003 is an apocalyptic number.

413004044003 is a deficient number, since it is larger than the sum of its proper divisors (1).

413004044003 is an equidigital number, since it uses as much as digits as its factorization.

413004044003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 413004044003 its reverse (300440400314), we get a palindrome (713444444317).

The spelling of 413004044003 in words is "four hundred thirteen billion, four million, forty-four thousand, three".