Base | Representation |
---|---|
bin | 111100000110011010010… |
… | …010001111100110111001 |
3 | 112121211101102120010012111 |
4 | 330012122102033212321 |
5 | 1020131321310421431 |
6 | 12441153020412321 |
7 | 604246353103633 |
oct | 74063222174671 |
9 | 15554342503174 |
10 | 4130052045241 |
11 | 13525aa7890a1 |
12 | 5685220a70a1 |
13 | 23c6016c3565 |
14 | 103c776b5a53 |
15 | 7267369e7b1 |
hex | 3c19a48f9b9 |
4130052045241 has 2 divisors, whose sum is σ = 4130052045242. Its totient is φ = 4130052045240.
The previous prime is 4130052045209. The next prime is 4130052045247. The reversal of 4130052045241 is 1425402500314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4003116606841 + 126935438400 = 2000779^2 + 356280^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130052045241 - 25 = 4130052045209 is a prime.
It is a super-2 number, since 2×41300520452412 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4130052045247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065026022620 + 2065026022621.
It is an arithmetic number, because the mean of its divisors is an integer number (2065026022621).
Almost surely, 24130052045241 is an apocalyptic number.
It is an amenable number.
4130052045241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130052045241 is an equidigital number, since it uses as much as digits as its factorization.
4130052045241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 4130052045241 its reverse (1425402500314), we get a palindrome (5555454545555).
The spelling of 4130052045241 in words is "four trillion, one hundred thirty billion, fifty-two million, forty-five thousand, two hundred forty-one".
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