Base | Representation |
---|---|
bin | 111100000110011101110… |
… | …111000100101001001010 |
3 | 112121211112121102201121121 |
4 | 330012131313010221022 |
5 | 1020131432140000211 |
6 | 12441203002225454 |
7 | 604251012012262 |
oct | 74063567045112 |
9 | 15554477381547 |
10 | 4130112031306 |
11 | 135263062a558 |
12 | 56853a1b528a |
13 | 23c610c67081 |
14 | 103c8164c7a2 |
15 | 72678a9d271 |
hex | 3c19ddc4a4a |
4130112031306 has 4 divisors (see below), whose sum is σ = 6195168046962. Its totient is φ = 2065056015652.
The previous prime is 4130112031289. The next prime is 4130112031307. The reversal of 4130112031306 is 6031302110314.
4130112031306 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4127662672225 + 2449359081 = 2031665^2 + 49491^2 .
It is a super-2 number, since 2×41301120313062 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4130112031307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1032528007825 + ... + 1032528007828.
Almost surely, 24130112031306 is an apocalyptic number.
4130112031306 is a deficient number, since it is larger than the sum of its proper divisors (2065056015656).
4130112031306 is a wasteful number, since it uses less digits than its factorization.
4130112031306 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2065056015655.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 4130112031306 in words is "four trillion, one hundred thirty billion, one hundred twelve million, thirty-one thousand, three hundred six".
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