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41301131 is a prime number
BaseRepresentation
bin1001110110001…
…1010010001011
32212201022111112
42131203102023
541033114011
64033120535
71011024314
oct235432213
985638445
1041301131
112134a173
12119b914b
138730b51
1456b160b
15395c58b
hex276348b

41301131 has 2 divisors, whose sum is σ = 41301132. Its totient is φ = 41301130.

The previous prime is 41301119. The next prime is 41301149. The reversal of 41301131 is 13110314.

41301131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41301131 - 210 = 41300107 is a prime.

It is a super-2 number, since 2×413011312 = 3411566843758322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41301181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20650565 + 20650566.

It is an arithmetic number, because the mean of its divisors is an integer number (20650566).

Almost surely, 241301131 is an apocalyptic number.

41301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41301131 is an equidigital number, since it uses as much as digits as its factorization.

41301131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 41301131 is about 6426.5955995379. The cubic root of 41301131 is about 345.6638649183.

Adding to 41301131 its reverse (13110314), we get a palindrome (54411445).

The spelling of 41301131 in words is "forty-one million, three hundred one thousand, one hundred thirty-one".