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413015131 is a prime number
BaseRepresentation
bin11000100111100…
…001110001011011
31001210011100020201
4120213201301123
51321212441011
6104552203031
713143366514
oct3047416133
91053140221
10413015131
111a2155421
12b6399477
136774a669
143cbd1a0b
15263d4cc1
hex189e1c5b

413015131 has 2 divisors, whose sum is σ = 413015132. Its totient is φ = 413015130.

The previous prime is 413015123. The next prime is 413015137. The reversal of 413015131 is 131510314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 413015131 - 23 = 413015123 is a prime.

It is a super-2 number, since 2×4130151312 = 341162996869894322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 413015099 and 413015108.

It is not a weakly prime, because it can be changed into another prime (413015137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206507565 + 206507566.

It is an arithmetic number, because the mean of its divisors is an integer number (206507566).

Almost surely, 2413015131 is an apocalyptic number.

413015131 is a deficient number, since it is larger than the sum of its proper divisors (1).

413015131 is an equidigital number, since it uses as much as digits as its factorization.

413015131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 413015131 is about 20322.7737034097. The cubic root of 413015131 is about 744.7125182412.

Adding to 413015131 its reverse (131510314), we get a palindrome (544525445).

The spelling of 413015131 in words is "four hundred thirteen million, fifteen thousand, one hundred thirty-one".