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413022435041 is a prime number
BaseRepresentation
bin1100000001010100000…
…11100011011011100001
31110111002020120121112202
412000222003203123201
523231332220410131
6513423452102545
741561036525636
oct6005203433341
91414066517482
10413022435041
1114a186440607
1268068464a55
132cc425668c8
1415dc18cc18d
15ab24cccbcb
hex602a0e36e1

413022435041 has 2 divisors, whose sum is σ = 413022435042. Its totient is φ = 413022435040.

The previous prime is 413022435019. The next prime is 413022435073. The reversal of 413022435041 is 140534220314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 400163782225 + 12858652816 = 632585^2 + 113396^2 .

It is a cyclic number.

It is not a de Polignac number, because 413022435041 - 222 = 413018240737 is a prime.

It is a super-3 number, since 3×4130224350413 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 413022434995 and 413022435013.

It is not a weakly prime, because it can be changed into another prime (413024435041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206511217520 + 206511217521.

It is an arithmetic number, because the mean of its divisors is an integer number (206511217521).

Almost surely, 2413022435041 is an apocalyptic number.

It is an amenable number.

413022435041 is a deficient number, since it is larger than the sum of its proper divisors (1).

413022435041 is an equidigital number, since it uses as much as digits as its factorization.

413022435041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 413022435041 its reverse (140534220314), we get a palindrome (553556655355).

The spelling of 413022435041 in words is "four hundred thirteen billion, twenty-two million, four hundred thirty-five thousand, forty-one".