Base | Representation |
---|---|
bin | 111100000110101010011… |
… | …001101010000011110011 |
3 | 112121212002021022210012111 |
4 | 330012222121222003303 |
5 | 1020132400020032201 |
6 | 12441235515510151 |
7 | 604256145223225 |
oct | 74065231520363 |
9 | 15555067283174 |
10 | 4130322424051 |
11 | 135272937075a |
12 | 568598758357 |
13 | 23c64571c915 |
14 | 103ca1578415 |
15 | 7268c2abb51 |
hex | 3c1aa66a0f3 |
4130322424051 has 2 divisors, whose sum is σ = 4130322424052. Its totient is φ = 4130322424050.
The previous prime is 4130322423961. The next prime is 4130322424069. The reversal of 4130322424051 is 1504242230314.
4130322424051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4130322424051 - 219 = 4130321899763 is a prime.
It is not a weakly prime, because it can be changed into another prime (4130322424091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065161212025 + 2065161212026.
It is an arithmetic number, because the mean of its divisors is an integer number (2065161212026).
Almost surely, 24130322424051 is an apocalyptic number.
4130322424051 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130322424051 is an equidigital number, since it uses as much as digits as its factorization.
4130322424051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 4130322424051 its reverse (1504242230314), we get a palindrome (5634564654365).
The spelling of 4130322424051 in words is "four trillion, one hundred thirty billion, three hundred twenty-two million, four hundred twenty-four thousand, fifty-one".
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