Base | Representation |
---|---|
bin | 111100000110101010111… |
… | …011111100101001101111 |
3 | 112121212002220020110212100 |
4 | 330012222323330221233 |
5 | 1020132404320204403 |
6 | 12441240440310143 |
7 | 604256314512330 |
oct | 74065273745157 |
9 | 15555086213770 |
10 | 4130331413103 |
11 | 1352733450325 |
12 | 56859b772353 |
13 | 23c64754929c |
14 | 103ca2838287 |
15 | 7268ce852a3 |
hex | 3c1aaefca6f |
4130331413103 has 96 divisors (see below), whose sum is σ = 7330083531264. Its totient is φ = 2187325679616.
The previous prime is 4130331413071. The next prime is 4130331413113. The reversal of 4130331413103 is 3013141330314.
4130331413103 is a `hidden beast` number, since 4 + 1 + 30 + 3 + 314 + 1 + 310 + 3 = 666.
It is not a de Polignac number, because 4130331413103 - 25 = 4130331413071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4130331413113) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 204999676 + ... + 205019822.
It is an arithmetic number, because the mean of its divisors is an integer number (76355036784).
Almost surely, 24130331413103 is an apocalyptic number.
4130331413103 is a deficient number, since it is larger than the sum of its proper divisors (3199752118161).
4130331413103 is a wasteful number, since it uses less digits than its factorization.
4130331413103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23101 (or 23098 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 4130331413103 its reverse (3013141330314), we get a palindrome (7143472743417).
The spelling of 4130331413103 in words is "four trillion, one hundred thirty billion, three hundred thirty-one million, four hundred thirteen thousand, one hundred three".
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