Base | Representation |
---|---|
bin | 1100000001010101011… |
… | …00100111101100100111 |
3 | 1110111002222211112212121 |
4 | 12000222230213230213 |
5 | 23231342444403143 |
6 | 513424514530411 |
7 | 41561230163614 |
oct | 6005254475447 |
9 | 1414088745777 |
10 | 413033200423 |
11 | 14a191523818 |
12 | 6806bb96a07 |
13 | 2cc4486595c |
14 | 15dc30d150b |
15 | ab25c077ed |
hex | 602ab27b27 |
413033200423 has 4 divisors (see below), whose sum is σ = 416048041440. Its totient is φ = 410018359408.
The previous prime is 413033200403. The next prime is 413033200441. The reversal of 413033200423 is 324002330314.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 413033200423 - 237 = 275594246951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (413033200403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1507420303 + ... + 1507420576.
It is an arithmetic number, because the mean of its divisors is an integer number (104012010360).
Almost surely, 2413033200423 is an apocalyptic number.
413033200423 is a deficient number, since it is larger than the sum of its proper divisors (3014841017).
413033200423 is a wasteful number, since it uses less digits than its factorization.
413033200423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3014841016.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 413033200423 its reverse (324002330314), we get a palindrome (737035530737).
The spelling of 413033200423 in words is "four hundred thirteen billion, thirty-three million, two hundred thousand, four hundred twenty-three".
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