Base | Representation |
---|---|
bin | 101110111101010001010011… |
… | …0110000000000101111011111 |
3 | 2000011110100120021101212020221 |
4 | 1131322202212300000233133 |
5 | 413114231400401304120 |
6 | 4022244302531022211 |
7 | 153000146202251506 |
oct | 13572424660005737 |
9 | 2004410507355227 |
10 | 413041212525535 |
11 | 10a675881565850 |
12 | 3a3aa1a243a967 |
13 | 14961808547149 |
14 | 73dd430cab83d |
15 | 32b423a95e0aa |
hex | 177a8a6c00bdf |
413041212525535 has 32 divisors (see below), whose sum is σ = 559472866836480. Its totient is φ = 289973375529600.
The previous prime is 413041212525521. The next prime is 413041212525569. The reversal of 413041212525535 is 535525212140314.
It is not a de Polignac number, because 413041212525535 - 213 = 413041212517343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413041212525491 and 413041212525500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20119647 + ... + 35083936.
It is an arithmetic number, because the mean of its divisors is an integer number (17483527088640).
Almost surely, 2413041212525535 is an apocalyptic number.
413041212525535 is a deficient number, since it is larger than the sum of its proper divisors (146431654310945).
413041212525535 is a wasteful number, since it uses less digits than its factorization.
413041212525535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55208319.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 413041212525535 its reverse (535525212140314), we get a palindrome (948566424665849).
The spelling of 413041212525535 in words is "four hundred thirteen trillion, forty-one billion, two hundred twelve million, five hundred twenty-five thousand, five hundred thirty-five".
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