Base | Representation |
---|---|
bin | 111100000110110000011… |
… | …010100001001011110101 |
3 | 112121212100022011111000110 |
4 | 330012300122201023311 |
5 | 1020133101332010031 |
6 | 12441253522133233 |
7 | 604261511610426 |
oct | 74066032411365 |
9 | 15555308144013 |
10 | 4130423313141 |
11 | 135278030a174 |
12 | 5686064b1219 |
13 | 23c6605b4cc8 |
14 | 103cb0b1b64d |
15 | 72696089c46 |
hex | 3c1b06a12f5 |
4130423313141 has 16 divisors (see below), whose sum is σ = 5600877952320. Its totient is φ = 2706797174400.
The previous prime is 4130423313119. The next prime is 4130423313151. The reversal of 4130423313141 is 1413133240314.
It is not a de Polignac number, because 4130423313141 - 25 = 4130423313109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4130423313099 and 4130423313108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4130423313151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2686161 + ... + 3933993.
It is an arithmetic number, because the mean of its divisors is an integer number (350054872020).
Almost surely, 24130423313141 is an apocalyptic number.
It is an amenable number.
4130423313141 is a deficient number, since it is larger than the sum of its proper divisors (1470454639179).
4130423313141 is a wasteful number, since it uses less digits than its factorization.
4130423313141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1266596.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 4130423313141 its reverse (1413133240314), we get a palindrome (5543556553455).
The spelling of 4130423313141 in words is "four trillion, one hundred thirty billion, four hundred twenty-three million, three hundred thirteen thousand, one hundred forty-one".
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