Base | Representation |
---|---|
bin | 101110111101101110001010… |
… | …1110011000000001111101011 |
3 | 2000011200021120122102002221011 |
4 | 1131323130111303000033223 |
5 | 413121240331002414201 |
6 | 4022332554215324351 |
7 | 153004502345530432 |
oct | 13573342563001753 |
9 | 2004607518362834 |
10 | 413103205123051 |
11 | 10a69a0a3793913 |
12 | 3a3ba2036806b7 |
13 | 14967607a59201 |
14 | 7402432250119 |
15 | 32b5b680b1151 |
hex | 177b715cc03eb |
413103205123051 has 2 divisors, whose sum is σ = 413103205123052. Its totient is φ = 413103205123050.
The previous prime is 413103205122977. The next prime is 413103205123109. The reversal of 413103205123051 is 150321502301314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413103205123051 - 223 = 413103196734443 is a prime.
It is not a weakly prime, because it can be changed into another prime (413103205123151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206551602561525 + 206551602561526.
It is an arithmetic number, because the mean of its divisors is an integer number (206551602561526).
Almost surely, 2413103205123051 is an apocalyptic number.
413103205123051 is a deficient number, since it is larger than the sum of its proper divisors (1).
413103205123051 is an equidigital number, since it uses as much as digits as its factorization.
413103205123051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 413103205123051 its reverse (150321502301314), we get a palindrome (563424707424365).
The spelling of 413103205123051 in words is "four hundred thirteen trillion, one hundred three billion, two hundred five million, one hundred twenty-three thousand, fifty-one".
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