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41311032041 is a prime number
BaseRepresentation
bin100110011110010101…
…000101001011101001
310221122000222212100202
4212132111011023221
51134101111011131
630551130441545
72661503656436
oct463625051351
9127560885322
1041311032041
111657a0008a4
12800ab932b5
133b84880a76
141ddc760b8d
15111bb55bcb
hex99e5452e9

41311032041 has 2 divisors, whose sum is σ = 41311032042. Its totient is φ = 41311032040.

The previous prime is 41311031999. The next prime is 41311032071. The reversal of 41311032041 is 14023011314.

41311032041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22073342041 + 19237690000 = 148571^2 + 138700^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41311032041 is a prime.

It is not a weakly prime, because it can be changed into another prime (41311032071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20655516020 + 20655516021.

It is an arithmetic number, because the mean of its divisors is an integer number (20655516021).

Almost surely, 241311032041 is an apocalyptic number.

It is an amenable number.

41311032041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41311032041 is an equidigital number, since it uses as much as digits as its factorization.

41311032041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 41311032041 its reverse (14023011314), we get a palindrome (55334043355).

The spelling of 41311032041 in words is "forty-one billion, three hundred eleven million, thirty-two thousand, forty-one".