413111004121 has 4 divisors (see below), whose sum is σ = 414236647552. Its totient is φ = 411985360692.

The previous prime is 413111004071. The next prime is 413111004127. The reversal of 413111004121 is 121400111314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413111004121 - 2¹⁵ = 413110971353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413111004127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562821165 + ... + 562821898.

It is an arithmetic number, because the mean of its divisors is an integer number (103559161888).

Almost surely, 2^413111004121 is an apocalyptic number.

It is an amenable number.

413111004121 is a deficient number, since it is larger than the sum of its proper divisors (1125643431).

413111004121 is a wasteful number, since it uses less digits than its factorization.

413111004121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1125643430.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 413111004121 its reverse (121400111314), we get a palindrome (534511115435).

The spelling of 413111004121 in words is "four hundred thirteen billion, one hundred eleven million, four thousand, one hundred twenty-one".