Base | Representation |
---|---|
bin | 10010110010010011111101… |
… | …11000111100110110010001 |
3 | 12102021022020021122001000111 |
4 | 21121021332320330312101 |
5 | 20403320140310431231 |
6 | 223510022444321321 |
7 | 11462426112600115 |
oct | 1131117670746621 |
9 | 172238207561014 |
10 | 41311124311441 |
11 | 12187a49771086 |
12 | 4772457b43241 |
13 | 1a088122929ba |
14 | a2b67d253745 |
15 | 4b98e55894b1 |
hex | 25927ee3cd91 |
41311124311441 has 2 divisors, whose sum is σ = 41311124311442. Its totient is φ = 41311124311440.
The previous prime is 41311124311423. The next prime is 41311124311469. The reversal of 41311124311441 is 14411342111314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22644654649600 + 18666469661841 = 4758640^2 + 4320471^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41311124311441 is a prime.
It is not a weakly prime, because it can be changed into another prime (41311124311241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20655562155720 + 20655562155721.
It is an arithmetic number, because the mean of its divisors is an integer number (20655562155721).
Almost surely, 241311124311441 is an apocalyptic number.
It is an amenable number.
41311124311441 is a deficient number, since it is larger than the sum of its proper divisors (1).
41311124311441 is an equidigital number, since it uses as much as digits as its factorization.
41311124311441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4608, while the sum is 31.
Adding to 41311124311441 its reverse (14411342111314), we get a palindrome (55722466422755).
The spelling of 41311124311441 in words is "forty-one trillion, three hundred eleven billion, one hundred twenty-four million, three hundred eleven thousand, four hundred forty-one".
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