Search a number
-
+
41311414121 is a prime number
BaseRepresentation
bin100110011110010110…
…100010011101101001
310221122001201021110212
4212132112202131221
51134101210222441
630551142550505
72661510140405
oct463626423551
9127561637425
1041311414121
111657a24196a
12800b138435
133b84985953
141ddc820105
15111bbcdeeb
hex99e5a2769

41311414121 has 2 divisors, whose sum is σ = 41311414122. Its totient is φ = 41311414120.

The previous prime is 41311414103. The next prime is 41311414127. The reversal of 41311414121 is 12141411314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39915644521 + 1395769600 = 199789^2 + 37360^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41311414121 is a prime.

It is not a weakly prime, because it can be changed into another prime (41311414127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20655707060 + 20655707061.

It is an arithmetic number, because the mean of its divisors is an integer number (20655707061).

Almost surely, 241311414121 is an apocalyptic number.

It is an amenable number.

41311414121 is a deficient number, since it is larger than the sum of its proper divisors (1).

41311414121 is an equidigital number, since it uses as much as digits as its factorization.

41311414121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 23.

Adding to 41311414121 its reverse (12141411314), we get a palindrome (53452825435).

The spelling of 41311414121 in words is "forty-one billion, three hundred eleven million, four hundred fourteen thousand, one hundred twenty-one".