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413122140455441 is a prime number
BaseRepresentation
bin101110111101110110111111…
…0011011100100001000010001
32000011202002110021120122210012
41131323231332123210020101
5413122043120424033231
64022345405153244305
7153006042522306224
oct13573557633441021
92004662407518705
10413122140455441
1110a6a713024034a
123a401a08b63695
13149693349a42c1
14740330ad935bb
1532b63c5624e2b
hex177bb7e6e4211

413122140455441 has 2 divisors, whose sum is σ = 413122140455442. Its totient is φ = 413122140455440.

The previous prime is 413122140455419. The next prime is 413122140455459. The reversal of 413122140455441 is 144554041221314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 382568563609600 + 30553576845841 = 19559360^2 + 5527529^2 .

It is a cyclic number.

It is not a de Polignac number, because 413122140455441 - 222 = 413122136261137 is a prime.

It is not a weakly prime, because it can be changed into another prime (413122140055441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206561070227720 + 206561070227721.

It is an arithmetic number, because the mean of its divisors is an integer number (206561070227721).

Almost surely, 2413122140455441 is an apocalyptic number.

It is an amenable number.

413122140455441 is a deficient number, since it is larger than the sum of its proper divisors (1).

413122140455441 is an equidigital number, since it uses as much as digits as its factorization.

413122140455441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 307200, while the sum is 41.

Adding to 413122140455441 its reverse (144554041221314), we get a palindrome (557676181676755).

The spelling of 413122140455441 in words is "four hundred thirteen trillion, one hundred twenty-two billion, one hundred forty million, four hundred fifty-five thousand, four hundred forty-one".