Base | Representation |
---|---|
bin | 1100000001100001000… |
… | …01101100110110011001 |
3 | 1110111100210212100101010 |
4 | 12000300201230312121 |
5 | 23232043014014431 |
6 | 513442331044133 |
7 | 41563525366320 |
oct | 6006041546631 |
9 | 1414323770333 |
10 | 413131001241 |
11 | 14a231752a42 |
12 | 680988a0649 |
13 | 2cc5bbb946a |
14 | 15dd20ad0b7 |
15 | ab2e5c5846 |
hex | 603086cd99 |
413131001241 has 16 divisors (see below), whose sum is σ = 642927273984. Its totient is φ = 231051987984.
The previous prime is 413131001131. The next prime is 413131001263. The reversal of 413131001241 is 142100131314.
It is not a de Polignac number, because 413131001241 - 218 = 413130739097 is a prime.
It is a super-2 number, since 2×4131310012412 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (413131001291) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209285235 + ... + 209287208.
It is an arithmetic number, because the mean of its divisors is an integer number (40182954624).
Almost surely, 2413131001241 is an apocalyptic number.
It is an amenable number.
413131001241 is a deficient number, since it is larger than the sum of its proper divisors (229796272743).
413131001241 is a wasteful number, since it uses less digits than its factorization.
413131001241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418572500.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 413131001241 its reverse (142100131314), we get a palindrome (555231132555).
The spelling of 413131001241 in words is "four hundred thirteen billion, one hundred thirty-one million, one thousand, two hundred forty-one".
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