Base | Representation |
---|---|
bin | 10010110010010111101010… |
… | …10111100000001111111011 |
3 | 12102021111100210212201100202 |
4 | 21121023311113200033323 |
5 | 20403333223140013001 |
6 | 223510552012152415 |
7 | 11462526300130403 |
oct | 1131136527401773 |
9 | 172244323781322 |
10 | 41313112032251 |
11 | 12188879791154 |
12 | 477291176870b |
13 | 1a08a6b02ac67 |
14 | a2b7cb233803 |
15 | 4b99aed2396b |
hex | 2592f55e03fb |
41313112032251 has 2 divisors, whose sum is σ = 41313112032252. Its totient is φ = 41313112032250.
The previous prime is 41313112032229. The next prime is 41313112032263. The reversal of 41313112032251 is 15223021131314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41313112032251 is a prime.
It is not a weakly prime, because it can be changed into another prime (41313112037251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20656556016125 + 20656556016126.
It is an arithmetic number, because the mean of its divisors is an integer number (20656556016126).
Almost surely, 241313112032251 is an apocalyptic number.
41313112032251 is a deficient number, since it is larger than the sum of its proper divisors (1).
41313112032251 is an equidigital number, since it uses as much as digits as its factorization.
41313112032251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 41313112032251 its reverse (15223021131314), we get a palindrome (56536133163565).
The spelling of 41313112032251 in words is "forty-one trillion, three hundred thirteen billion, one hundred twelve million, thirty-two thousand, two hundred fifty-one".
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