Base | Representation |
---|---|
bin | 10010110010100101000001… |
… | …10111110010110001001110 |
3 | 12102022011212122220010021200 |
4 | 21121102200313302301032 |
5 | 20403442420244233300 |
6 | 223514135424210330 |
7 | 11463202111024200 |
oct | 1131224067626116 |
9 | 172264778803250 |
10 | 41320284367950 |
11 | 1219091a343115 |
12 | 47741937699a6 |
13 | 1a09641c53393 |
14 | a2bcaba10770 |
15 | 4b9c7e830200 |
hex | 2594a0df2c4e |
41320284367950 has 216 divisors, whose sum is σ = 131255567197560. Its totient is φ = 9289806019200.
The previous prime is 41320284367939. The next prime is 41320284367961. The reversal of 41320284367950 is 5976348202314.
41320284367950 is a `hidden beast` number, since 4 + 1 + 320 + 284 + 36 + 7 + 9 + 5 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (41320284367939) and next prime (41320284367961).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 14015080 + ... + 16705179.
It is a 1-persistent number, because it is pandigital, but 2⋅41320284367950 = 82640568735900 is not.
Almost surely, 241320284367950 is an apocalyptic number.
41320284367950 is an abundant number, since it is smaller than the sum of its proper divisors (89935282829610).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41320284367950 is a wasteful number, since it uses less digits than its factorization.
41320284367950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30720352 (or 30720337 counting only the distinct ones).
The product of its (nonzero) digits is 8709120, while the sum is 54.
The spelling of 41320284367950 in words is "forty-one trillion, three hundred twenty billion, two hundred eighty-four million, three hundred sixty-seven thousand, nine hundred fifty".
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