Base | Representation |
---|---|
bin | 111100001000101000101… |
… | …000110000111001011001 |
3 | 112122001112212111201020222 |
4 | 330020220220300321121 |
5 | 1020201214210012213 |
6 | 12442230013325425 |
7 | 604362503045645 |
oct | 74105050607131 |
9 | 15561485451228 |
10 | 4132440313433 |
11 | 1353615908363 |
12 | 568a89a96875 |
13 | 23c8c24322c3 |
14 | 10402295dc25 |
15 | 727631a9808 |
hex | 3c228a30e59 |
4132440313433 has 2 divisors, whose sum is σ = 4132440313434. Its totient is φ = 4132440313432.
The previous prime is 4132440313363. The next prime is 4132440313439. The reversal of 4132440313433 is 3343130442314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4086268188304 + 46172125129 = 2021452^2 + 214877^2 .
It is a cyclic number.
It is not a de Polignac number, because 4132440313433 - 222 = 4132436119129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4132440313393 and 4132440313402.
It is not a weakly prime, because it can be changed into another prime (4132440313439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066220156716 + 2066220156717.
It is an arithmetic number, because the mean of its divisors is an integer number (2066220156717).
Almost surely, 24132440313433 is an apocalyptic number.
It is an amenable number.
4132440313433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4132440313433 is an equidigital number, since it uses as much as digits as its factorization.
4132440313433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 4132440313433 its reverse (3343130442314), we get a palindrome (7475570755747).
The spelling of 4132440313433 in words is "four trillion, one hundred thirty-two billion, four hundred forty million, three hundred thirteen thousand, four hundred thirty-three".
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