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413244302101 = 439610332607
BaseRepresentation
bin1100000001101110100…
…01111010001100010101
31110111122201001121221021
412000313101322030111
523232311020131401
6513501455321141
741566402416451
oct6006721721425
91414581047837
10413244302101
1114a28a6a9614
126810a8201b1
132cc795090a7
1416003163661
15ab395062a1
hex603747a315

413244302101 has 4 divisors (see below), whose sum is σ = 422854634752. Its totient is φ = 403633969452.

The previous prime is 413244302083. The next prime is 413244302111. The reversal of 413244302101 is 101203442314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 413244302101 - 231 = 411096818453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413244302111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4805166261 + ... + 4805166346.

It is an arithmetic number, because the mean of its divisors is an integer number (105713658688).

Almost surely, 2413244302101 is an apocalyptic number.

It is an amenable number.

413244302101 is a deficient number, since it is larger than the sum of its proper divisors (9610332651).

413244302101 is an equidigital number, since it uses as much as digits as its factorization.

413244302101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9610332650.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 413244302101 its reverse (101203442314), we get a palindrome (514447744415).

The spelling of 413244302101 in words is "four hundred thirteen billion, two hundred forty-four million, three hundred two thousand, one hundred one".

Divisors: 1 43 9610332607 413244302101