41330134401041 has 2 divisors, whose sum is σ = 41330134401042. Its totient is φ = 41330134401040.

The previous prime is 41330134400969. The next prime is 41330134401067. The reversal of 41330134401041 is 14010443103314.

41330134401041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36446829968641 + 4883304432400 = 6037121^2 + 2209820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41330134401041 is a prime.

It is a super-2 number, since 2×41330134401041² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41330134400995 and 41330134401013.

It is not a weakly prime, because it can be changed into another prime (41330134401071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20665067200520 + 20665067200521.

It is an arithmetic number, because the mean of its divisors is an integer number (20665067200521).

Almost surely, 2^{41330134401041} is an apocalyptic number.

It is an amenable number.

41330134401041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41330134401041 is an equidigital number, since it uses as much as digits as its factorization.

41330134401041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 41330134401041 its reverse (14010443103314), we get a palindrome (55340577504355).

The spelling of 41330134401041 in words is "forty-one trillion, three hundred thirty billion, one hundred thirty-four million, four hundred one thousand, forty-one".