Base | Representation |
---|---|
bin | 101110111111001111100010… |
… | …1100111000001001111000010 |
3 | 2000012102021022202011010100012 |
4 | 1131332133011213001033002 |
5 | 413133202104134422402 |
6 | 4023013015551224522 |
7 | 153025554264055343 |
oct | 13576370547011702 |
9 | 2005367282133305 |
10 | 413312313201602 |
11 | 10a76a849855261 |
12 | 3a432841518142 |
13 | 1498125103a279 |
14 | 740c5cbc3c0ca |
15 | 32bb305e60452 |
hex | 177e7c59c13c2 |
413312313201602 has 4 divisors (see below), whose sum is σ = 619968469802406. Its totient is φ = 206656156600800.
The previous prime is 413312313201587. The next prime is 413312313201617. The reversal of 413312313201602 is 206102313213314.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (413312313201587) and next prime (413312313201617).
It can be written as a sum of positive squares in only one way, i.e., 326194338844201 + 87117974357401 = 18060851^2 + 9333701^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 103328078300399 + ... + 103328078300402.
Almost surely, 2413312313201602 is an apocalyptic number.
413312313201602 is a deficient number, since it is larger than the sum of its proper divisors (206656156600804).
413312313201602 is a wasteful number, since it uses less digits than its factorization.
413312313201602 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 206656156600803.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 413312313201602 its reverse (206102313213314), we get a palindrome (619414626414916).
The spelling of 413312313201602 in words is "four hundred thirteen trillion, three hundred twelve billion, three hundred thirteen million, two hundred one thousand, six hundred two".
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