Base | Representation |
---|---|
bin | 10010110010111101011110… |
… | …11001100011001110101111 |
3 | 12102100102202121201201220021 |
4 | 21121132233121203032233 |
5 | 20404201312212000421 |
6 | 223524150252303011 |
7 | 11464145335404541 |
oct | 1131365731431657 |
9 | 172312677651807 |
10 | 41333413000111 |
11 | 12196447095841 |
12 | 4776838471a67 |
13 | 1a0a954b8208b |
14 | a2c7954a1691 |
15 | 4ba29c1e0341 |
hex | 2597af6633af |
41333413000111 has 4 divisors (see below), whose sum is σ = 41334128131752. Its totient is φ = 41332697868472.
The previous prime is 41333413000067. The next prime is 41333413000129. The reversal of 41333413000111 is 11100031433314.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41333413000111 - 223 = 41333404611503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41333413000811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357479116 + ... + 357594721.
It is an arithmetic number, because the mean of its divisors is an integer number (10333532032938).
Almost surely, 241333413000111 is an apocalyptic number.
41333413000111 is a deficient number, since it is larger than the sum of its proper divisors (715131641).
41333413000111 is an equidigital number, since it uses as much as digits as its factorization.
41333413000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 715131640.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 41333413000111 its reverse (11100031433314), we get a palindrome (52433444433425).
The spelling of 41333413000111 in words is "forty-one trillion, three hundred thirty-three billion, four hundred thirteen million, one hundred eleven", and thus it is an aban number.
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