Base | Representation |
---|---|
bin | 10010110010111110100110… |
… | …00111000011101100100011 |
3 | 12102100111022101002210112002 |
4 | 21121133103013003230203 |
5 | 20404204024101212011 |
6 | 223524325533554215 |
7 | 11464166232060245 |
oct | 1131372307035443 |
9 | 172314271083462 |
10 | 41334012132131 |
11 | 12196724300574 |
12 | 477698504596b |
13 | 1a0aa1c035874 |
14 | a2c810ca0095 |
15 | 4ba2d4adac3b |
hex | 2597d31c3b23 |
41334012132131 has 2 divisors, whose sum is σ = 41334012132132. Its totient is φ = 41334012132130.
The previous prime is 41334012132109. The next prime is 41334012132151. The reversal of 41334012132131 is 13123121043314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41334012132131 is a prime.
It is a super-2 number, since 2×413340121321312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41334012132094 and 41334012132103.
It is not a weakly prime, because it can be changed into another prime (41334012132151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20667006066065 + 20667006066066.
It is an arithmetic number, because the mean of its divisors is an integer number (20667006066066).
Almost surely, 241334012132131 is an apocalyptic number.
41334012132131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41334012132131 is an equidigital number, since it uses as much as digits as its factorization.
41334012132131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 41334012132131 its reverse (13123121043314), we get a palindrome (54457133175445).
The spelling of 41334012132131 in words is "forty-one trillion, three hundred thirty-four billion, twelve million, one hundred thirty-two thousand, one hundred thirty-one".
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