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41334012132131 is a prime number
BaseRepresentation
bin10010110010111110100110…
…00111000011101100100011
312102100111022101002210112002
421121133103013003230203
520404204024101212011
6223524325533554215
711464166232060245
oct1131372307035443
9172314271083462
1041334012132131
1112196724300574
12477698504596b
131a0aa1c035874
14a2c810ca0095
154ba2d4adac3b
hex2597d31c3b23

41334012132131 has 2 divisors, whose sum is σ = 41334012132132. Its totient is φ = 41334012132130.

The previous prime is 41334012132109. The next prime is 41334012132151. The reversal of 41334012132131 is 13123121043314.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41334012132131 is a prime.

It is a super-2 number, since 2×413340121321312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41334012132094 and 41334012132103.

It is not a weakly prime, because it can be changed into another prime (41334012132151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20667006066065 + 20667006066066.

It is an arithmetic number, because the mean of its divisors is an integer number (20667006066066).

Almost surely, 241334012132131 is an apocalyptic number.

41334012132131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41334012132131 is an equidigital number, since it uses as much as digits as its factorization.

41334012132131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 41334012132131 its reverse (13123121043314), we get a palindrome (54457133175445).

The spelling of 41334012132131 in words is "forty-one trillion, three hundred thirty-four billion, twelve million, one hundred thirty-two thousand, one hundred thirty-one".