Base | Representation |
---|---|
bin | 1111011001011110… |
… | …1110001000111001 |
3 | 101200001202011021102 |
4 | 3312113232020321 |
5 | 31431123212213 |
6 | 1522053221145 |
7 | 204300302012 |
oct | 36627561071 |
9 | 11601664242 |
10 | 4133413433 |
11 | 1831227766 |
12 | 9743317b5 |
13 | 50b463a86 |
14 | 2b2d62009 |
15 | 192d2a158 |
hex | f65ee239 |
4133413433 has 2 divisors, whose sum is σ = 4133413434. Its totient is φ = 4133413432.
The previous prime is 4133413429. The next prime is 4133413441. The reversal of 4133413433 is 3343143314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4132946944 + 466489 = 64288^2 + 683^2 .
It is a cyclic number.
It is not a de Polignac number, because 4133413433 - 22 = 4133413429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4133413396 and 4133413405.
It is not a weakly prime, because it can be changed into another prime (4133413423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066706716 + 2066706717.
It is an arithmetic number, because the mean of its divisors is an integer number (2066706717).
Almost surely, 24133413433 is an apocalyptic number.
It is an amenable number.
4133413433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4133413433 is an equidigital number, since it uses as much as digits as its factorization.
4133413433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 29.
The square root of 4133413433 is about 64291.6280164066. The cubic root of 4133413433 is about 1604.8567831241.
Adding to 4133413433 its reverse (3343143314), we get a palindrome (7476556747).
The spelling of 4133413433 in words is "four billion, one hundred thirty-three million, four hundred thirteen thousand, four hundred thirty-three".
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