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4134104442551 = 36749112495699
BaseRepresentation
bin111100001010001011110…
…100111010011010110111
3112122012211211212020020202
4330022023310322122313
51020213121214130201
612443103101351115
7604451650651226
oct74121364723267
915565754766222
104134104442551
11135429a200186
1256927326849b
1323cac912c5a5
1410413d988cbd
157280e324c6b
hex3c28bd3a6b7

4134104442551 has 4 divisors (see below), whose sum is σ = 4134216975000. Its totient is φ = 4133991910104.

The previous prime is 4134104442541. The next prime is 4134104442563. The reversal of 4134104442551 is 1552444014314.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4134104442551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4134104442541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56211101 + ... + 56284598.

It is an arithmetic number, because the mean of its divisors is an integer number (1033554243750).

Almost surely, 24134104442551 is an apocalyptic number.

4134104442551 is a deficient number, since it is larger than the sum of its proper divisors (112532449).

4134104442551 is a wasteful number, since it uses less digits than its factorization.

4134104442551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112532448.

The product of its (nonzero) digits is 153600, while the sum is 38.

Adding to 4134104442551 its reverse (1552444014314), we get a palindrome (5686548456865).

The spelling of 4134104442551 in words is "four trillion, one hundred thirty-four billion, one hundred four million, four hundred forty-two thousand, five hundred fifty-one".

Divisors: 1 36749 112495699 4134104442551